re: Question about 'Top reasons for random, fatal crashes in Windows XP and Windows 2000'
Thursday, December 12, 2002 at 2:19 pm
Windows 2000 Annoyances Discussion Forum
Posted by Gail
(2 messages posted)
Valerie - while bits and bytes are counted in multiples of 8 (16, 32...128,512) it
is easiest to think of the KB/MB conversion in terms of the metric system. So move
the decimal place for 129,524 over 3 places and round to the nearest standard multiple
of 8. Starting with 129,524 you move the decimal over and get 129 and then round
to 128 (since the next standard multiple is 512).
Hope that helps with the next time you need to figure it out.
On Saturday, December 7, 2002 at 9:06 am, valerie wrote:
>Can someone tell me how to interpret the following amount of ram that I have on
my
>system, or tell me how I can equate it my self.
>
>The total amount I am showing is 129,524 kb ram....any help?
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